sinθの係数√3の2乗は3
cosθの係数3の2乗は9
3+9=12
12の正の平方根は2√3
よって式を2√3でくくると
2√3(1/2 sinθ + √3/2 cosθ)
=2√3(sinθcos60+cosθsin60)
=2√3sin(θ+60)
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
詳説【数学Ⅰ】第一章 数と式～整式・実数・不等式～
4462
117
詳説【数学Ａ】第２章 確率
3587
26
詳説【数学Ⅰ】第二章 ２次関数（前半）～関数とグラフ～
3180
15
詳説【数学Ａ】第１章 個数の処理（集合・場合の数・順列組合）
3025
46