△DEFと△ABCにおいて
外角の定理より
∠DEF=∠ABE+∠BAE
∠DFE=∠FCB+∠FBC
ここで
∠BAE=∠FBC
∠FBC=∠DCA
であるから
∠DEF=∠ABE+∠FBC=∠ABC・・・①
∠DFE=∠FCB+∠DCA=∠ACB・・・②
①②より2組の角が各々等しいので
△DEF∽△ABC
Answers
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