大きい方の奇数を2m+1
小さい方の奇数を2n+1とすると、
(2m+1)^2-(2n+1)^2
=(4m^2+4m+1)-(4n^2+4n+1)
=4m^2+4m-4n^2-4n
=4(m^2+m-n^2-n)
となって4の倍数となる。
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大きい方の奇数を2m+1
小さい方の奇数を2n+1とすると、
(2m+1)^2-(2n+1)^2
=(4m^2+4m+1)-(4n^2+4n+1)
=4m^2+4m-4n^2-4n
=4(m^2+m-n^2-n)
となって4の倍数となる。
Users viewing this question
are also looking at these questions 😉
