(1)用向量內積→垂直=0求點A B
(2)用(1)的解[(Xa-Xb)^2+(Ya-Yb)^2]^1/2即為所求
(3)外接圓心=三中垂線交點
先求線段AB與線段PA的中點座標
垂直的話斜率相乘等於-1求中點到圓心
的斜率
用點斜式y-y¡=m(x-X¡)
求出兩線方程式後解聯立即可得到所求
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