道幅をxとする。
(16-x)(25-x)=360
400-41x+xの2乗=360
xの2乗-41x+40=0
(x-1)(x-40)=0
x=1,40
ここで0＜x＜16より、x=1。
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道幅をxとする。
(16-x)(25-x)=360
400-41x+xの2乗=360
xの2乗-41x+40=0
(x-1)(x-40)=0
x=1,40
ここで0＜x＜16より、x=1。
答.1m
Users viewing this question
are also looking at these questions 😉
