Mathematics
Senior High
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y=x^xの微分がわかりません

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✨ Best Answer ✨

y' を求めればよいわけです

y = x^x ではわかりにくいので
対数をとります

logy = logx^x
logy = xlogx となります

両辺を y で微分します

1/dy logy = 1/dy xlogx
1/y = dx/dy 1/dx xlogx
1/y = 1/y' (logx + 1)
y' = y(logx + 1)
=x^x (logx + 1)

となります

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